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(F)=4F-F^2/3
We move all terms to the left:
(F)-(4F-F^2/3)=0
We get rid of parentheses
F^2/3-4F+F=0
We multiply all the terms by the denominator
F^2-4F*3+F*3=0
Wy multiply elements
F^2-12F+3F=0
We add all the numbers together, and all the variables
F^2-9F=0
a = 1; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·1·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*1}=\frac{0}{2} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*1}=\frac{18}{2} =9 $
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